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a 0.380 m solution of kcl needs to be prepared through dilution. a 2.00 m stock solution will be added to a 0.250 l volumetric flask and then water will be added to the 0.250 l mark. determine the volume (in ml) of the 2.00 m stock solution of kcl needed to produce this solution.

Respuesta :

Taking into account the definition of dilution, the volume of the 2.00 M stock solution of KCl needed to produce the solution is 47.5 mL.

Dilution:

Dilution is the process of creating a less concentrated solution from a more concentrated one. Simply adding more solvent at the same solute concentration makes it happen.

The concentration of the solute falls when additional solvent is added, despite the fact that the amount of solute remains constant as the volume of the solution rises.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentration

Vi: initial volume

Cf: final concentration

Vf: final volume

Volume of the stock solution

In this case, you know:

Ci= 2 M

Vi= ?

Cf= 0.380 M

Vf= 0.250 L

Replacing in the definition of dilution:

2 M× Vi= 0.380 M× 0.250 L

Solving:

Vi= (0.380 M× 0.250 L)÷ 2 M

Vi= 0.0475 L= 47.5 mL (being 1 L= 1000 mL)

In summary, 47.5 mL of stock solution are needed.

To know more about Dilution visit:

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