A car loses value each year the value of the car (t) years ‏ can be modeled using the function f(t)=15000(0.85) ^t. If Elizabeth wants to sell her car in 2 1/3 years what will the cars value be when she sells it?

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31-01-2018
Mathematics

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A car loses value each year the value of the car (t) years ‏ can be modeled using the function f(t)=15000(0.85) ^t. If Elizabeth wants to sell her car in 2 1/3 years what will the cars value be when she sells it?

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altavistard altavistard · Answer 1 · 2018-01-31T01:26:25+01:00

altavistard altavistard

31-01-2018

f(t)=15000(0.85) ^t => f(t) = $15000(0.85) ^t

Substitute 2 1/3 for t in this equation. This is equivalent to 7/3.

f(7/3) = $15000(0.85)^(7/3)
= $10266.02 (answer)

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