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Two capacitors, C1 and C2, give an equivalent capacitance of 9.0 pF when connected in parallel and an equivalent capacitance of 2.0 pF when connected in series. What is the capacitance of each capacitor? C1 = _______ pF (smallest value) C2 = __________ pF (largest value)

Respuesta :

Answer:

C₁ = 3 pF

C₂ = 6 pF

Explanation:

Let the capacitance be C₁ and C₂.

For parallel combination

C₁ +C₂ = 9

For series combination

[tex]2=\frac{C_1\times C_2}{C_1+C_2}[/tex]

[tex]2=\frac{C_1\times C_2}{9}[/tex]

C₁ X C₂ = 18

( 9-C₂ )X C₂ = 18

C₂²- 9C₂ +18 = 0

C₂ = 6 or 3.

C₁ = 3 or 6.

C₁ = 3 pF

C₂ = 6 pF

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