Respuesta :

AL2006
Log(x+6) = log(x-3) + log(2).

(X+6) = 2 (x-3)

X+6 = 2x - 6

6 = x-6

X = 12

Solution:

[tex] log(x + 6) = log(x - 3) + log(2) \\ = > log(x + 6) = log(x - 3) (2) \\ = > x + 6 = 2x - 6 \\ = > x - 2x = - 6 - 6 \\ = > - x = - 12 \\ = > x = 12[/tex]

Answer:

x = 12

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