Respuesta :

Space

Answer:

0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Distributive Property

Algebra I

  • Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

(-5x + 6x²) - (6x² - 5x)

Step 2: Simplify

  1. [Distributive Property] Distribute negative:                                                    -5x + 6x² - 6x² + 5x
  2. [Subtraction] Combine like terms (x²):                                                             -5x + 5x
  3. [Addition] Combine like terms (x):                                                                   0

Answer:

❊ [tex] \large{ \tt{STEP - BY - STEP \: EXPLANATION}} : [/tex]

♡ Firstly , Here are some of the questions & their answers which should be known before simplifying the given expression :

Q. Do I have to change the sign of each term of second expression while subtracting ?

Ans : Yep! While subtracting , sign of each term of the second expression changes whereas In addition , sign of each term in the expressions remains unchanged.

Q. What do you mean by Like terms & Unlike terms ?

Ans : Well , Like terms are those which have the same base whereas Unlike terms are those which have the different base [ For eg : In 4x , 2y , 3x & 4y , 4x & 3x are like terms and 2y and 4y are like terms ]. Also Remember : Only coefficients of like terms can be added or subtracted.

The Question / Answer part ends up here. Now , Let's get started for simplifying the given expression :

[tex] \large{ \bf{❊ \: ( - 5 {x}^{} + 6 {x}^{2} ) - (6 {x }^{2} - 5x)}}[/tex]

[tex] \large{ \bf{ ↬ \: - 5x + 6 {x}^{2} - 6 {x}^{2} + 5x}}[/tex]

[tex] \large{ \bf{↬ - 5x + 5x + 6 {x}^{2} - 6 {x}^{2} }}[/tex]

-Here , We can see the like terms with different signs. So, they cancel out each other.

[tex] \large{ \bf{↬ \: \cancel{5x} + \cancel{5x}} + \cancel{6 {x}^{2}} - \cancel{6 {x}}^{2} }[/tex]

-We're left with nothing , So the answer would be ' 0 ' .

[tex] \boxed{ \large{ \bf{↬0}}}[/tex]

[tex] \boxed{ \boxed {\large{ \tt{⟿ \: OUR\: FINAL \: ANSWER : \boxed{ \underline{ \bf{0}}}}}}}[/tex]

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