in a certain examination, 72 candidates offered mathematics, 64 offered English, and 62 offered french, 18 offered both mathematics and English, 24 offered mathematics and French, and 20 offered English and French, 8 candidates offered all the three subjects. how many candidates were there for the examination​

Respuesta :

Answer:

Step-by-step explanation:

To find the total number of candidates for the examination, you can use the principle of inclusion-exclusion. This principle helps you account for the overlaps between different sets.

Let's denote:

- \(M\) as the set of candidates who offered Mathematics,

- \(E\) as the set of candidates who offered English,

- \(F\) as the set of candidates who offered French.

The total number of candidates (\(N\)) can be expressed as:

\[ N = |M \cup E \cup F| \]

Using the inclusion-exclusion principle, this is given by:

\[ N = |M| + |E| + |F| - |M \cap E| - |M \cap F| - |E \cap F| + |M \cap E \cap F| \]

Now, let's plug in the given values:

\[ N = 72 + 64 + 62 - 18 - 24 - 20 + 8 \]

Calculate each term:

\[ N = 142 - 62 \]

So, the total number of candidates for the examination is \(80\).