Answer:
0.05 moles of sodium sulfate are required.
Explanation:
[tex]Na_2SO_4(s) \rightarrow 2Na^+ (aq) SO_4^{2-} (aq)[/tex]
Concentration of sodium ions in 1 L = 0.10 M
[tex]0.10 M=\frac{\text{Moles of sodium ions}}{1.0 L}[/tex]
Moles of sodium ions = 0.10 mol
1 mole of sodium sulfate gives 2 moles of sodium ions.
Then 0.10 mol of sodium ions will be given by:
[tex]\frac{1}{2}\times 0.10 mol=0.05 mol[/tex]
0.05 moles of sodium sulfate are required.
