Given
[tex]\frac{2x^6-9x^5+4x^2-5}{x^3-5}[/tex]
To rewrite the above expression as,
[tex]q(x)+\frac{r(x)}{b(x)}[/tex]
and find q(x).
Explanation:
It is given that,
[tex]\frac{2x^6-9x^5+4x^2-5}{x^3-5}[/tex]
That implies,
Therefore,
[tex]\frac{2x^{6}-9x^{5}+4x^{2}-5}{x^{3}-5}=(2x^3-9x^2+10)+\frac{45-41x^2}{x^3-5}[/tex]
Hence,
[tex]q(x)=2x^3-9x^2+10[/tex]
