A 3,000 kg truck moving at +10m/s hits a 1,000 kg parked car which moved off at +15m/s. What is the velocity of the truck

Respuesta :

Given,

The mass of the truck, M=3000 kg

The mass of the car, m=1000 kg

The velocity of the truck before the collision, u=10 m/s

The velocity of the car after the collision, v₁=15 m/s

From the law of conservation of momentum, the total momentum of the car and the truck before the collision is equal to their total momentum after the collision.

Thus,

[tex]Mu=mv_1+Mv_2[/tex]

Where v₂ is the velocity of the truck after the collision.

On rearranging the above equation,

[tex]v_2=\frac{Mu-mv_1}{M}[/tex]

On substituting the known values,

[tex]\begin{gathered} v_2=\frac{3000\times10-1000\times15}{3000} \\ =5\text{ m/s} \end{gathered}[/tex]

Therefore the velocity of the truck after it hits the car is 5 m/s