We know that the acceleration is 0.4 m/s2 which means that we have a constant acceleration. Then we have an uniformly accelerated motion, then we can use the equation:
[tex]y=v_0t+\frac{1}{2}at^2[/tex]In this case the initial velocity is zero, the time is 20 seconds and the acceleration is -0.4 m/s2, plugging these values we have:
[tex]\begin{gathered} y=(0)(20)-\frac{1}{2}(0.4)(20)^2 \\ y=-80 \end{gathered}[/tex]Therefore, the load will move 80 meters down in twenty seconds.
