Take into account the following equivalence between number of electrons and 1 Coulomb:
[tex]1C=6.2415\cdot10^{18}electrons[/tex]Then, by using the previous equality, you have:
[tex]1.88\cdot10^{18}\text{electrons}\cdot\frac{1C}{6.2415\cdot10^{18}\text{electrons}}=0.3C[/tex]Then, approximately 0.3 coulombs of charge were moved.
And the current in the circuit is:
[tex]I=\frac{0.3C}{0.5s}=0.6A[/tex]The current in the circuit is 0.6A
