If the number of bacteria in a colony doubles every 72 hours and there is currently a population of 105,700 bacteria, what will the population be 216 hours from now? bacteria

Respuesta :

EXPLANATION

Let's see the facts:

Period = 72 hours

Initial Population= 105,700

Time = 216 hours

The equation is as follows:

[tex]P=P_0e^{rt}^{}[/tex]

P_0=Initial Population

r= rate of growth

t=time

First, we need to find r:

In 72 hours ------> 2*105,700 = 211,400 bacteria

Replacing terms:

[tex]211,400=105,700e^{(r72)}[/tex]

Dividing both sides by 105,700:

[tex]\frac{211,400}{105,700}=e^{(72r)}[/tex]

Applying ln to both sides:

[tex]\ln (\frac{211,400}{105,700})=\ln (e^{72r})[/tex]

Simplifying:

[tex]\ln (\frac{211,400}{105,700})=72r\cdot\ln e[/tex]

Dividing both sides by 72:

[tex]\frac{\ln (\frac{211,400}{105,700})}{72}=r[/tex]

Switching sides:

[tex]r=\frac{\ln (\frac{2114}{1057})}{72}[/tex]

Simplifying:

[tex]r=\frac{0.69}{72}=0.009627[/tex]

Now that we have r=0.009627 we can calculate the value of P as shown as follows:

[tex]P=105,700e^{(0.009627\cdot216)}[/tex]

Multiplying terms:

[tex]P=105,700\cdot e^{(2.08)}^{}[/tex]

Now, we can solve the expression:

[tex]P=105,700\cdot8=845,600[/tex]

The answer is 845,600 bacteria.