We have the next function
[tex]g(x)=\frac{x+1}{x^2+2x+1}[/tex]
And we must find the values of x that are not in the domain of g.
since the functions is a faction the values of x where the function is not defined are the values that x takes when the denominator is equal to 0
To find these values we must equal the denomintor to 0 and then solve it for x
[tex]x^2+2x+1=0[/tex]
factoring,
[tex]\begin{gathered} (x+1)^2=0 \\ x+1=0 \\ x=-1 \end{gathered}[/tex]
Finally, the value of x that is not in the domain of g is -1
ANSWER:
[tex]x=-1[/tex]
