The gas in a cylinder has a volume of 5 liters at a pressure of 115 kPa. The pressure of the gas is increased to 211 kPa. Assuming the temperature remains constant, what would the new volume be?
We know the initial pressure and volume, the final pressure, and the temperature is constant, Using the G.U.E.S.S. method we can express the problem like this: [tex]Givens: V_1=5 L, P_1= 115kPa, P_2= 211kPa
[/tex] [tex]Unknown: V_2[/tex] [tex]Equation: \frac{V_1P_1}{P_2}=V_2 [/tex] [tex]Substitute: \frac{5L*115kPa}{211kPa}= V_2[/tex] [tex]Solve: \frac{5L*115kPa}{211kPa}= 2.73 or 2.72L[/tex]
In conclusion, your answer is either 2.73 kPa if you round or 2.72 kPa if you don't. Hope you learned from it.
