1) We can sketch a triangle for that problem, angles of depression/elevation are usually found by applying the tangent ratio
[tex]\begin{gathered} \tan(38)=\frac{50}{x} \\ x\tan(38)_=50 \\ \frac{x\tan(38)}{\tan(38)}=\frac{50}{\tan(38)} \\ x=63.9970\approx64\:m \end{gathered}[/tex]Rounding off to the nearest whole we can tell the answer is:
[tex]64\:m\:(approximately)[/tex]