Respuesta :
The velocity of the ball going when it reaches the base of the hill will be 5.5 m/sec.
What is velocity?
The change of distance concerning time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The complete question is;
A 10 kg ball is released from the top of a hill. How fast is the ball going when it reaches the base of the hill? Approximate g as 10 m/s2 and round the answer to the nearest tenth.
hy = 2 m
h = 0.5 m
The given data in the problem is
m is the mass of block = 10 Kg
u is the initial velocity of fall = 0 m/sec
h is the distance of fall = 2.5 m
g is the acceleration of free fall =10 m/sec²
v is the hitting velocity of =?
According to Newton's third equation of motion;
[tex]\rm v^2=u^2+2g(h_2-h_1) \\\\ \rm v^2=0+2g(h_2-h_1) \\\\ v = \sqrt{2g(h_2-h_1)}\\\\ v = \sqrt{2 \times 9.81 \times (2-0.5)|}\\\\ v =\sqrt{2 \times 9.81 \times 1.5 } \\\\ v = 5.5 \ m/sec[/tex]
Hence, the velocity of the ball going when it reaches the base of the hill will be 5.5 m/sec.
To learn more about the velocity refer to the link;
https://brainly.com/question/862972
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