The concentration of the sulfuric acid will be 0.124 M
From the equation of the reaction:
[tex]H_2SO_4 + 2KOH --- > K_2SO_4 + 2H_2O[/tex]
The mole ratio of the sulfuric acid to the KOH is 1:2.
Mole of 0.220 M, 22.5 mL KOH = 0.220 x 22.5/1000 = 0.00495 moles
Equivalent mole of the sulfuric acid = 0.00495/2 = 0.002475 moles
Molarity of 20.0 mL 0.002475 moles sulfuric acid = 0.002475/0.02 = 0.124 M
More on calculating molarity can be found here: https://brainly.com/question/15948514
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