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An airplane is flying in a horizontal circle at a speed of 490 km/h. If its wings are tilted at angle ɵ = 45° to the horizontal, what is the radius of the circle in which the plane is flying? Assume that the required force is provided entirely by an “aerodynamic lift” that is perpendicular to the wing surface.

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The radius of the circle in which the plane is flying is 1887 m.

What is aerodynamic lift?

The aerodynamic lift is the force that keeps the aircraft flying in the air.

Let the  aerodynamic lift be F1 sinθ= mv^2/R ---- (1)

and F1 cosθ= mg --------- (2)

Equating (1) and (2) and eliminating the mass;

R = v^2/ g tanθ

Where v = 490 km/h or 136 m/s

R = (136)^2/9.8 * tan 45

R = 18496/ 9.8

R = 1887 m

Learn more about aerodynamic lift:https://brainly.com/question/14890260

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