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A ball is projected horizontally from the top of the building of height 50 m with a horizonatal velocity of 4m/sec. What is the range of the ball? (physics)​

Respuesta :

Answer:

12.78metres

Explanation:

it is a falling body projectile motion that Range

R = VoCosøt but ø= 0 no angle

R = Vot

and t is given by Newton's second eqn as

t=√(2h/g)

thus R=Vo√(2h/g)

upon substitution

R= 12.78