If the 72% of its original amount of C-14. Then the number of years will be 3285.
The complete question is attached below.
Let b is the base and x is the power of the exponent function and a is the leading coefficient. The exponent is given as
y = a(b)ˣ
A hiker in Africa discovers a skull that contains 72% of its original amount of C- 14.
Then the function is given below.
[tex]\rm N= N_0 \ e^{-kt}[/tex]
Where, N₀ is the initial amount of C - 14, t is the number of the years, k is constant that is 0.0001, and N be the amount of the C - 14 at t years.
[tex]\rm N= N_0 \ e^{-0.0001 \times t}[/tex]
We have N = 0.72N₀, the time will be
[tex]\rm 0.72N_0 = N_0 \ e^{-0.0001 \times t}\\\\\rm 0.72 \ \ \ \ = \ e^{-0.0001 \times t}[/tex]
Take log on both side, then we have
ln 0.72 = -0.001 × t × ln e
-0.33 = -0.001 × t
t = 3285 years
More about the exponent link is given below.
https://brainly.com/question/5497425
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