Respuesta :

Considering the reaction stoichiometry, the mass of oxygen gas that is required to produce 32.1 grams of maleic acid anhydride is 47.17 grams.

The balanced reaction is:

2 C₆H₆(l) + 9 O₂(g)→ 2 C₄H₂O₃(s) + 4 CO₂(g) + 4 H₂O(g)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • C₆H₆: 2 moles
  • O₂: 9  moles
  • C₄H₂O₃: 2 moles
  • CO₂: 4 moles
  • H₂O: 4 moles

The molar mass of each compound is:

  • C₆H₆: 78 g/mole
  • O₂: 32 g/mole
  • C₄H₂O₃: 98 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole

By reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:

  • C₆H₆: 2 moles× 78 g/mole= 156 grams
  • O₂: 9 moles× 32 g/mole= 288 grams
  • C₄H₂O₃: 2 moles× 98 g/mole= 196 grams
  • CO₂: 4 moles× 44 g/mole= 176 grams
  • H₂O: 4 moles× 18 g/mole= 72 grams

Then you can apply the following rule of three: If by stoichiometries 196 grams of C₄H₂O₃ are produced by 288 grams of O₂, 32.1 grams of C₄H₂O₃ are produced from how much mass of O₂?

[tex]mass of O_{2} =\frac{32.1 grams of C_{4} H_{2} O_{3} x288 grams of O_{2}}{196grams of C_{4} H_{2} O_{3}}[/tex]

mass of O₂= 47.17 grams

Finally, the mass of oxygen gas that is required to produce 32.1 grams of maleic acid anhydride is 47.17 grams.  

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