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A 1391.3 kg car is traveling at 29.8 m/s when the driver takes his foot off the gas pedal. It takes 4.9 s for the car to slow down to 20 m/s. How large is the net force slowing the car

Respuesta :

Answer:

Fnet = 2782.6 N

Explanation:

  • Newton's 2nd Law states that the net force applied to an object, is equal to its mass times the acceleration.
  • By definition, acceleration is the rate of change of velocity with respect to time, as follows:

        [tex]a = \frac{\Delta v}{\Delta t}[/tex]

        where Δv = vf - v₀ and Δt = tfi - t₀, replacing by the givens:

       [tex]\Delta v = v_{f} - v_{o} = 20 m/s - 29.8 m/s = -9.8 m/s[/tex]

       Δt = 4.9 s

       ⇒[tex]a = \frac{-9.8m/s}{4.9s} = -2 m/s2[/tex]

  • We can now apply Newton's 2nd Law, solving for Fnet, as follows:

        [tex]F_{net} = m* a = 1391.1 kg * (-2 m/s2) = -2782.6 N[/tex]

  • The magnitude of the is net force (How large it is ) is just:
  • Fnet = 2782.6 N