Answer:
The probability that no more than '2' customers will arrive in minute = 1.5412
Step-by-step explanation:
Explanation:-
Mean of the Poisson distribution 'λ' = 2 per minute
P(X=x) = e⁻ˣ λˣ/x!
The probability that no more than '2' customers will arrive in minute
P(x≤ 2) = P(x=0) +P(x=1)+P(x=2)
= e⁻² (2)°/0! + e⁻²(2)¹/1!+e⁻² (2)²/2!
= 1 + 0.2706 + 0.2706
= 1.5412
The probability that no more than '2' customers will arrive in minute = 1.5412
