Respuesta :
Answer:
Since [tex]P(A \cap B) \neq P(A)P(B)[/tex], these events are not independent.
Step-by-step explanation:
Independent events:
Two events, A and B are independent, if:
[tex]P(A \cap B) = P(A)P(B)[/tex]
In this question, we have that:
[tex]P(A) = 0.4, P(B) = 0.2, P(A \cap B) = 0.1[/tex]
However
[tex]P(A)P(B) = 0.4*0.02 = 0.08[/tex]
Since [tex]P(A \cap B) \neq P(A)P(B)[/tex], these events are not independent.
