Answer: The osmotic pressure of the solution is 7.44 atm
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
[tex]\pi=iMRT[/tex]
or,
[tex]\pi=i\times \frac{m_{solute}\times 1000}{M_{solute}\times V_{solution}\text{ (in mL)}}}\times RT[/tex]
where,
[tex]\pi[/tex] = osmotic pressure of the solution = ?
i = Van't hoff factor = 1 (for non-electrolytes)
[tex]m_{solute}[/tex] = given mass of glucose = 11.9 g
[tex]M_{solute}[/tex] = molar mass of glucose = 180.2 g/mol
[tex]V_{solution}[/tex] = Volume of solution = 217 mL
R = Gas constant = [tex]0.0821\text{ L atm }mol^{-1}K^{-1}[/tex]
T = temperature of the solution = 298 K
Putting values in above equation, we get:
[tex]\pi=1\times \frac{11.9\times 1000}{180.2\times 217}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\\pi=7.44atm[/tex]
Hence, the osmotic pressure of the solution is 7.44 atm
