Given:
[tex]\begin{gathered} n=225 \\ mean(\mu)=6.4 \\ standard\text{ }deviation=4.1 \\ confidence\text{ }interval=99 \end{gathered}[/tex]
To Determine: The mean number of the unoccupied seat
Solution
The formula for finding confidence interval given
[tex]CI=\mu\pm z\times\frac{\sigma}{\sqrt{n}}[/tex]
