Answer:
The energy released is [tex]3.13\times 10^{7}\ C[/tex]
Explanation:
Potential difference between two prongs, V = 120 V
No. of moles of electrons, n = 2.7 moles
Now,
We know that the charge contained in 1 mole of an electron is given as:
1 mole = 96485 C
Thus
The charge in 2.7 moles of electrons:
Q = [tex]2.7\times 96485 = 260509.5\ C[/tex]
Now,
Energy released, E = QV
[tex]E = 260509.5\times 120 = 3.13\times 10^{7}\ C[/tex]
