Answer:
18 volt
Explanation:
We have given number of turns in primary [tex]N_1=500[/tex]
Primary voltage [tex]V_1=120volt[/tex]
Number of turns in secondary [tex]N_2=75[/tex]
For the transformer we know that [tex]\frac{N_1}{N_2}=\frac{V_1}{V_2}[/tex]
So [tex]\frac{500}{75}=\frac{120}{V_2}[/tex]
[tex]V_2=18\ volt[/tex]
So the induced voltage across secondary is 18 volt
