Given the trinomial x^2-bx-c where both the first and the second signs are negative, the signs of the factors will be:

A. cannot determine
B. both negative
C. both positive
D. one positive and one negative

Respuesta :

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

[tex]x^2-bx-c=0[/tex]

Both the first and second signs are negative,

Let α and β are the roots of the [tex]x^2-bx-c=0[/tex],

then, we know that the relationship between the zeroes and coefficients of quadratic equations:

[tex]\alpha+\beta =\frac{-b}{a}=b\\\\and\\\\\alpha \beta =\frac{-c}{a}=-c[/tex]

Since the product of roots is positive.

So, the signs of the factors will be one positive and one negative.

Hence, Option 'D' is correct.

Answer:

D

Step-by-step explanation: