Answer:
[tex](Base)=\sqrt{24} {\text{inches}[/tex]
Step-by-step explanation:
It is given that A right triangle has a leg of 5 inches and a hypotenuse of 7 inches, thus using the trigonometry, we have
[tex](Hyp)^2=(Base)^2+(Per)^2[/tex]
Substituting the given values, we have
[tex](7)^2=(Base)^2+(5)^2[/tex]
⇒[tex]49=(Base)^2+25[/tex]
⇒[tex]49-25=(Base)^2[/tex]
⇒[tex]24=(Base)^2[/tex]
⇒[tex](Base)=\sqrt{24} {\text{inches}[/tex]
Thus, the length of the other leg is [tex]\sqrt{24} {\text{inches}[/tex].
