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An auditorium has 80 rows of seats and the number of seats per row increases at a constant rate. If there are 32 seats in the 8th row, and 68 seats in the 20th row, how many seats are in the last row?

Respuesta :

To find how many seats in the 80th row, you need to figure out the pattern from the 8th row to the 20th row.

To do this, you can create a table showing possibilities from the 8th to the 20th.

I started with 32 at the 8th and added 2 each time.  This was only 56 by the 20th.

Then I added 3, and this got me to 68 by the 20th row.

Then you can work backwards to find how many seats in the 1st row.  I got 11.

From here you can create an equation that you could use to solve for the 80th row.

11 + 3(r - 1), where r is the number of rows.

Substitute in 80 for r.

11 + 3(80 - 1)
11 + 237
248 seats

There are 248 seats in the 80th row.
raphealnwobi

There are 248 seats are in the last row of the auditorium.

A linear equation is in the form:

y = mx + b;

where m is the rate of change, b is the initial value of y and y, x are variables.

Let y represent the number of seats in x rows.

There are 32 seats in the 8th row. Hence:

32 = 8m + b   (1)

There are 68 seats in the 20th row. Hence:

68 = 20m + b   (2)

Solving equation 1 and 2 simultaneously gives:

m = 3, b = 8

In the last row, x = 80:

y = 80(3) + 8 = 248

There are 248 seats are in the last row of the auditorium.

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The elevation of the road 4800 feet at the beginning and it gains elevation at a constant rate of 350 feet per mile.

Find out more at: brainly.com/question/25718473