Respuesta :
A = (0, 0)
B = (-2, -12)
y1 = ax + b
A:
0 = 0 · a + b
b = 0
B:
-12 = -2 · a + 0
-12 = -2a
a = 6
y1 = 6x
y1 ║ y
y = cx + d
c = a = 6
y = 6x + d
C = (6/5, -19/5)
C:
-19/5 = 6 · 6/5 + b
-19 = 36 + 5b
5b = -19 - 36
5b = -55
b = -11
y = 6x - 11
Answer A.
B = (-2, -12)
y1 = ax + b
A:
0 = 0 · a + b
b = 0
B:
-12 = -2 · a + 0
-12 = -2a
a = 6
y1 = 6x
y1 ║ y
y = cx + d
c = a = 6
y = 6x + d
C = (6/5, -19/5)
C:
-19/5 = 6 · 6/5 + b
-19 = 36 + 5b
5b = -19 - 36
5b = -55
b = -11
y = 6x - 11
Answer A.