Respuesta :

Total number of possible outcomes = 36

Total number of outcomes with sum even = 18

P(even) = 18/36 = 1/2

Answer: 1/2
konrad509

[tex] |\Omega|=6^2=36\\
|A|=\underbrace{3\cdot3}_{\text{O,O}}+\underbrace{3\cdot3}_{\text{E,E}}=18\\\\
P(A)=\dfrac{18}{36}=\dfrac{1}{2}=50\% [/tex]