you need to use the definitions of sin and cos [tex]sinx = \frac{opp}{hyp} \\ cosx = \frac{adj}{hyp} [/tex]from the question adj=7 ,hyp=25 since sin and cos are defined for a right triangle then [tex] {opp}^{2} + {adj}^{2} = {hyp}^{2} [/tex] solving for opp so we can find sin [tex]opp = \sqrt{ {hyp}^{2} - {adj}^{2} } [/tex] so plugging in the numbers [tex]opp = \sqrt{ {25}^{2} - {7}^{2} } = \sqrt{625 - 49} = \sqrt{576} = 24[/tex]
