the regular hexagon can be divided into 6 equilateral triangles
[area of regular hexagon]=6*[area of one equilateral triangle] area of one equilateral triangle=b*h/2 b=length side of a regular hexagon h=apothem-----> 4.33 cm area of one equilateral triangle=b*(4.33)/2------> 2.165*b cm²
[area of regular hexagon]=6*[area of one equilateral triangle] [area of regular hexagon]=64.95 cm² 64.95=6*[2.165*b]--------> b=64.95/[6*2.165]-----> b=5 cm
the length side of the regular hexagon is equal to the radius of the circle therefore
the radius required to inscribe a regular hexagon is 5 cm
