Consider the rate law below. R=k(NO2)^2 what happens to the rate if the concentration is tripled?
The rate increases by a factor of 9.
The rate decreases by a factor of 6.
The rate triples.
The rate doubles.
For this case we have the following equation: R = k (NO2) ^ 2 if the concentration is tripled, we must rewrite the equation. We have then: R '= k (3 * NO2) ^ 2 R '= 9 * k (NO2) ^ 2 Rewriting: R '= 9 * R Answer: The rate increases by a factor of 9.
