The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval, [tex]\Delta t[/tex]:
[tex]I= \frac{Q}{\Delta t} [/tex]
First we need to find the net charge flowing at a certain point of the wire in one second, [tex]\Delta t=1.0 s[/tex]. Using I=0.92 A and re-arranging the previous equation, we find
[tex]Q=I \Delta t= (0.92 A)(1.0 s)=0.92 C[/tex]
Now we know that each electron carries a charge of [tex]e=1.6 \cdot 10^{-19} C[/tex], so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second:
[tex]N= \frac{Q}{q} = \frac{0.92 C}{1.6 \cdot 10^{-19} C}=5.75 \cdot 10^{18} [/tex]
