Solve for x, given the equation Square root of x minus 5 + 7 = 11. x = 21, solution is extraneous x = 21, solution is not extraneous x = 81, solution is extraneous x = 81, solution is not extraneous
This is the concept of algebra, to solve the expression we proceed as follows: √(x-5)+7=11 put like terms together: √(x-5)=11-7 √(x-5)=4 squaring both sides we get: x-5=16 x=16+5 x=21 The solution is not extraneous.
