gandrapreetam gandrapreetam

30-03-2018
Mathematics

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If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2?

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altavistard altavistard

31-03-2018

Note that (a+b)^2 = a^2 + 2ab + b^2. This is always true.

Let's re-write the given "ab = 8 and a^2+b^2=16" as
a^2 + 2ab + b^2 = 16 + 2ab, or, equivalently, as
(a+b)^2 = 16 + 2(8) = 32.
This is the answer we wanted.

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