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(i) (a) what is the force per meter of length on a straight wire carrying a 9.75 a current when perpendicular to a 0.81 t uniform magnetic field?

Respuesta :

skyluke89
The force generated by a magnetic field B perpendicular to a wire carrying a current I is
[tex]F=ILB[/tex]
where L is the length of the wire.

If we divide both sides for L, we get
[tex] \frac{F}{L}=IB [/tex]
where the ratio on the left is the force per meter of length, which is exactly what we want to find. So:
[tex] \frac{F}{L}=IB=(9.75 A)(0.81 A)=7.90 N/m [/tex]

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