Sasha111111
Sasha111111
30-03-2018
Mathematics
contestada
who knows what is the answer?
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Louneave
Louneave
30-03-2018
set x=10 as equation 1 and 3x+5y=20 as equation 2
x=10----------(1)
3x+5y=20-----------(2)
substitute (1) into (2),
3(10)+5y=20
30+5y=20
30–20=–5y
10=–5y
5y=–10
y=–10÷5
y=–2
final ans:(10,–2)
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