Answer:
The Empirical formula of an organic compound is=[tex]C_3H_6O_2[/tex]
Explanation:
Mass of an organic compound = 200 g
Mass of carbon = 97.30 g
moles of carbon = [tex]\frac{97.30 g}{12 g/mol}=8.108 mol[/tex]
Mass of hydrogen = 16.22 g
Moles of hydrogen = [tex]\frac{16.22 g}{1 g/mol}=16.220 mol[/tex]
Mass of oxygen = 200 g - 97.30 g - 16.22 g = 86.48 g
Moles of oxygen =[tex]\frac{86.48 g}{16 g/mol}=5.405 mol[/tex]
Divide the all the moles of element with smallest value of moles.
Carbon = [tex]\frac{8.108 mol}{5.405 mol}=1.5[/tex]
Hydrogen = [tex]\frac{16.220 mol}{5.405 mol}=3[/tex]
Oxygen =[tex]\frac{5.405 mol}{5.405 mol}=1[/tex]
Empirical formula =[tex]C_{1.5}H_3O_1[/tex]
Converting them into whole number ratios.
Empirical formula =[tex]C_3H_6O_2[/tex]
