Respuesta :
The given equation is:
[tex]-3 x^{2} -2x+6=0[/tex]
a = coefficient of squared term = -3
b = co-efficient of x = -2
c = constant term = 6
Quadratic formula is:
[tex]x= \frac{-b+- \sqrt{ b^{2}-4ac } }{2a} [/tex]
Using the values of a,b and c, we can write:
[tex]x= \frac{-(-2)+- \sqrt{(-2)^{2}-4(-3)(6) } }{2(-3)} \\ \\ x= \frac{2+- \sqrt{76 } }{-6} \\ \\ [/tex]
The above formula correctly shows the substitution of values of a,b and c in the quadratic formula.
[tex]-3 x^{2} -2x+6=0[/tex]
a = coefficient of squared term = -3
b = co-efficient of x = -2
c = constant term = 6
Quadratic formula is:
[tex]x= \frac{-b+- \sqrt{ b^{2}-4ac } }{2a} [/tex]
Using the values of a,b and c, we can write:
[tex]x= \frac{-(-2)+- \sqrt{(-2)^{2}-4(-3)(6) } }{2(-3)} \\ \\ x= \frac{2+- \sqrt{76 } }{-6} \\ \\ [/tex]
The above formula correctly shows the substitution of values of a,b and c in the quadratic formula.
A quadratic equation is in the form of ax²+bx+c. The value of x is (2±√76)/(-6).
What is a quadratic equation?
A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.
It is written in the form of ax²+bx+c.
The given quadratic equation when compared to the general quadratic equation, the value of a, b and c will be,
a = coefficient of x² = -3
b = coefficient of x = -2
c = value of constant = 6
The solution of the quadratic equation can be found as,
[tex]x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-2)\pm \sqrt{(-2)^2-4(-3)(6)}}{2(-3)}\\\\x=\dfrac{2\pm \sqrt{4+72}}{-6}\\\\x=\dfrac{2\pm \sqrt{76}}{-6}[/tex]
Hence, the value of x is (2±√76)/(-6).
Learn more about Quadratic Equations:
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