the balanced equation for the above reaction is as follows; Fe₂O₃ + 3 CO --> 2 Fe + 3 CO₂ stoichiometry of CO to Fe is 3:2 molar volume states that 1 mol of any gas occupies a volume of 22.4 L If 22.4 L contains 1 mol of CO Then 3.65 L contains - 1/22.4 x 3.65 = 0.16 mol 3 mol of CO forms 2 mol of Fe Then 0.16 mol of CO forms - 2/3 x 0.16 = 0.1067 mol of Fe Therefore mass of Fe produced - 0.1067 mol x 55.8 g/mol = 5.95 g
