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Solve 2x2 − 8x = −7. (2 points)


A. negative 2 plus or minus square root of 2

B. negative 2 plus or minus 2 square root of 2

C. quantity of 2 plus or minus square root of 2 all over 2

D. 2 plus or minus square root of 2 end root over 2

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Answer:

D. 2 plus or minus square root of 2 end root over 2

Step-by-step explanation:

Given equation,

[tex]2x^2 - 8x = -7[/tex]

[tex]\implies 2x^2 - 8x + 7=0[/tex]

By the quadratic formula,

[tex]x=\frac{-(-8)\pm \sqrt{(-8)^2 -4\times 2\times 7}}{2\times 2}[/tex]

[tex]x=\frac{8\pm \sqrt{64 - 56}}{4}[/tex]

[tex]x=\frac{8\pm \sqrt{8}}{4}[/tex]

[tex]x=\frac{8\pm 2\sqrt{2}}{4}[/tex]

[tex]x=2\pm \frac{\sqrt{2}}{2}[/tex]

= 2 plus or minus square root of 2 end root over 2

OPTION D Is correct.

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