Respuesta :
Answer with Explanation:
A relation in a set is said to be function, if every first element of an ordered pair in a set is related with unique element of second element.
No,two distinct second element of an ordered pair,has same first element.
For,example ,{(1,2),(1,3),(4,5)}, is not a function but it is a relation.
In Ordered pair, (x,y)
x=First Element
y= Second Element
→In Set A
First Element Second Element
1 3
-1 5
6 4
Every First element of set A has unique second element. So, it is a function.
→In Set B
First Element Second Element
2 0
4 6
-4 5
0 0
Every First element of set B has unique second element and no two distinct Second element of set B,has same first element. So, it is a function.
→In Set C
First Element Second Element
1 1
0 2
0 3
-3 5
As, two same first element of set C has distinct second element. So, it is not a function.
Set A and Set B , are functions,but Set C is not.
Answer:
The sets A and B correctly represent functions.
Step-by-step explanation:
A set of ordered pairs in the format [tex](x,y)[/tex] represents a function if for each value of x, there is only one value for y.
The first set is A
A = {(1, 3)(-1, 5}(6, 4)}
For each value of x, there is only one value of y. So this set of relations correctly represents a function.
The second set is B
B = {(2, 0)(4, 6)(-4, 5)(0, 0)}
Again, for each value of x, there is only one value of y. So this set of relations correctly represents a function.
The third set is C
C = {(1, 1)(0, 2)(0, 3)(0, 4)(-3, 5)}
We have three values of y for x = 0. So this set does not represent a function.
