A compound contains potassium, nitrogen, and oxygen. the experimental analysis gave values of 45.942 % potassium and 16.458 % nitrogen, by weight, the remainder is oxygen. what is the empirical formula of the compound?

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Octaveace Octaveace · Answer 1 · 2018-03-28T11:05:49+02:00

it should be KNO3 to the best of my understanding

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dsdrajlin dsdrajlin · Answer 2 · 2019-12-22T19:11:34+01:00

Answer:

KNO₂

Explanation:

To get the empirical formula of a compound, we follow a series of steps.

Step 1: Given data

%K = 45.942%

%N = 16.458%

%O = 100.000% - 45.942% - 16.458% = 37.600%

Step 2: Divide each percentage by the atomic mass of the element

K: 45.942 / 39.098 = 1.1750

N: 16.458 / 14.007 = 1.1750

O: 37.600 / 15.999 = 2.3501

Step 3: We divide all the coefficients by the smallest number

K: 1.1750 / 1.1750 = 1

N: 1.1750 / 1.1750 = 1

O: 2.3501 / 1.1750 = 2

The empirical formula is KNO₂.