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A circular wire loop 51 cm in diameter has resistance 120 ω and lies in a horizontal plane. a uniform magnetic field points vertically downward, and in 25 ms it increases linearly from 5.0 mt to 55 mt. part a find the magnetic flux through the loop at the beginning.

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skyluke89
The radius of the wire loop is [tex]r= \frac{51 cm}{2}= 25.5 cm=0.255 m [/tex], so the area enclosed by the loop is
[tex]A=\pi r^2 = \pi (0.255 m)^2=0.204 m^2[/tex]

Initially, the magnetic field intensity is B=5.0 mT=0.005 T, so the magnetic flux throug the wire loop is
[tex]\Phi = BA=(0.005 T)(0.204 m^2)=1.02 \cdot 10^{-3} Wb[/tex]

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