Solve this system of equations: y = x2 – 3x + 12 y = –2x + 14 4. Substitute the values of x, –1 and 2, into either original equation to solve for the values of y. What are the solutions of the system of equations? One solution is (–1, ). The second solution (2, ).

Respuesta :

Answer:

(-1, 16) and (2, 10)

Step-by-step explanation:

Substituting -1 in place of x in the first equation, we have

y = (-1)²-3(-1)+12 = 1--3+12 = 1+3+12 = 4+12 = 16.

Substituting -1 in place of x in the second equation gives us

y=-2(-1)+14 = 2+14 = 16

This makes the first ordered pair (-1, 16).

Substituting 2 in place of x in the first equation gives us

y=2²-3(2)+12 = 4-6+12 = -2+12 = 10

Substituting 2 in place of x in the second equation gives us

y=-2(2)+14 = -4+14 = 10

This means the ordered pair (2, 10) is the second solution.

The solution of the equations y = x² – 3x + 12 and y = –2x + 14 are (–1, 16) and (2, 10).

What is the solution to the equations?

To solve the equations, the variable is to be compared.

The equation is given below.

y = x² – 3x + 12

y = –2x + 14

For x = –1, then the value of y will be for both equations.

y = (–1)² – 3(–1) + 12 = 16

y = –2(–1) + 14 = 16

Then the one solution is (–1, 16).

For x = 2, then the value of y will be for both equations.

y = (2)² – 3(2) + 12 = 10

y = –2(2) + 14 = 10

Then another solution is (2, 10).

More about the solution to the equation link is given below.

https://brainly.com/question/545403