Answer:
[tex]WV=\sqrt{40}\approx 6.32[/tex]
Step-by-step explanation:
We have been given a graph of coordinate plane. We are asked to find the length of segment WV.
Point W(-2,-2) and point V(0,4).
We will use distance formula to solve our given problem.
[tex]\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\text{Distance}=\sqrt{((0-(-2))^2+4-(-2))^2}[/tex]
[tex]\text{Distance}=\sqrt{(+2)^2+(4+2)^2}[/tex]
[tex]\text{Distance}=\sqrt{2^2+6^2}[/tex]
[tex]\text{Distance}=\sqrt{4+36}[/tex]
[tex]\text{Distance}=\sqrt{40}[/tex]
[tex]\text{Distance}=6.324555[/tex]
[tex]\text{Distance}\approx 6.32[/tex]
Therefore, the length of segment WV is approximately 6.32 units.
